how do you solve bx - cx = -c solving for x and then finding the restrictions
2007-08-28 09:14:51 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(b - c) x = - c
x = - c / (b - c) where (b - c) ≠ 0
2007-08-28 10:51:44 · answer #1 · answered by Como 7 · 3⤊ 0⤋
factor out the x to get x(b - c) = -c and x = c/(c - b)
A restriction might be something like dividing by 0 or taking a square root of a negative number. Something that violates some rule.
In this case you have something divided by something else. So a restriction would be when the denominator is 0. So b can not equal c.
2007-08-28 16:22:28 · answer #2 · answered by Captain Mephisto 7 · 0⤊ 0⤋
bx-cx = (b-c)*x = -c
thus
x = -c/(b-c) = c/(c-b)
Restrictions: x is only defined if the denominator is not zero, so b can't be c. That seems to be the only restriction...
2007-08-28 16:20:57 · answer #3 · answered by Nick S 5 · 0⤊ 0⤋
bx-cx=-c
Factot out x
x(b-c)=-c
Divide both sides by(b-c)
x=-c/(b-c)
Restrictions
(b-c) cannot equall 0
2007-08-28 16:29:47 · answer #4 · answered by scide i 2 · 0⤊ 0⤋
bx - cx = -c
x(b - c) = -c
x = -c/b-c with ''b -c'' different of 0
2007-08-28 16:21:31 · answer #5 · answered by frank 7 · 0⤊ 0⤋