Help with a simple trig limit?

1 ⤊

I'm a tad stuck with the following problem

lim theta^2 / sin(theta)

as theta -> 0

any ideas?

2007-08-28 08:57:07 · 2 answers · asked by AppleCard! 2 in Science & Mathematics ➔ Mathematics

I think

lim [theta / sin(theta)]=1
as theta -> 0

=> lim [ theta^2 / sin(theta)]
= lim [ theta / sin(theta) * theta ]
= 1 * 0
= 0

I hope

2007-08-28 09:07:34 · answer #1 · answered by harry m 6 · 1⤊ 1⤋

Use L'Hospital's Rule. The limit is 0.

2007-08-28 17:44:40 · answer #2 · answered by Tony 7 · 0⤊ 0⤋