I need help in solving linear equations by addition?

Question

8x-6y=10
33x-15y=12

Answer 1

8x - 6y = 10 ( x 5)
33x - 15y = 12 (x -2)

40x - 30y = 50
-66x + 30y = -24

Add the two eq'ns together

-26x = 26
x = -1
T o find y substitute -1 in for x.
8(-1) - 6y = 10
-8 - 6y = 10
- 6y = 18
y = -3
So answer is x = -1 and y = -3

Answer 2

(1) 8x-6y= 10
(2) 33x-15y = 12

(1) 6y = 8x-10
(1) 30y= 5(8x-10)

(2) 15y = 33x-12
(2) 30y = 2(33x -12)

Since 30y = 30y, we have 5(8x-10) = 2(33x-12)

40x-50 = 66x-24
40x-66x = -24 + 50
-26x = 26
x= -1

take either (1) or (2) and substitute x=-1 to get y.

(1) 6y = 8(-1) -10=-18

So y = -3

Answer: x= -1 and y = -3

Answer 3

8x - 6y =10 is the same as

-40x + 30y = -50

and 33x - 15y = 12 is the same as

66x - 30y = 24

put these together and get
26x = -26

so x =-1

sub in and we get
-8 - 6 y = 10

-6y = 18
y = -3

answer is x = -1 and y = -3

Answer 4

You need to eliminate one of the variables:
Multiply first by 5, and second by -2:
40x - 30y = 50
-66x + 30y = -24; now add:
-26x = 26, so x = -1
from first: -8 - 6y = 10, -6y = 18, so y = -3

Answer 5

multiply the 1st equation by 5 and 2nd equation by 2, and subtract the two equations to eliminate y,

40x - 30y - 66x + 30y = 50 - 24
-26x = 26
x = -1

substitute x in the 1st equation,
8(-1) -6y = 10
-6y = 18
y = -3

(-1, -3) is the solution.