Two planes leave chicago-one traveling due east and the other due west. The first travels 100 mph faster than the second. How long will it be untill they are 2000 miles apart? Please show the steps to get this.
2007-08-28 07:42:14 · 3 answers · asked by shawna 2 in Science & Mathematics ➔ Mathematics
x=speed of the first
x+100 = speed of the second
d1+d2=2000
xt + (x+100)t=2000
2xt+100t=2000
t(x+50)=1000
t=1000/(x+50)
2007-08-28 07:53:24 · answer #1 · answered by chasrmck 6 · 0⤊ 0⤋
d=speed x time
d1= (x+100)*time
d2= x * time
d1+d2=2000
2000 = xt + 100t +xt
2000 = 2xt + 100t
2000 = t(2x+100)
time = 2000 / (2x + 100)
where x = speedof the slower plane in mph
2007-08-28 14:54:45 · answer #2 · answered by skipper 7 · 0⤊ 0⤋
rate X time = distance.
x = rate of west bound plane
x+100 = rate of east bound plane
xt +(100+x)t = 2000
Two unknowns and only one equation.
Problem cannot be solved.
2007-08-28 14:57:38 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋