Inverse of each Function ?????

Question

The inverse of each function

f(x)= 3/4x

g(x)= 3+x
y=3x-2

Answer 1

y = 3/4x, so 4x = 3/y, and x = 3/4y

y = 3 + x, so x = y - 3

y = 3x-3, and 3x = y+3, so x = (y+3)/3

Answer 2

The way i understand it is that the inverse of a function is where the y or f(x) is transposed to the opposite side of the equation!! then x becomes y and y becomes x!! the range and the domain are reversed!! F(x) = 4x+4 becomes x=4y+4 where F(x) is substituted with y !! and x= y^2-9 Domain and range are inverted!!!

Answer 3

f^-1 (x) = 4/3x
g^-1 (x) = x-3
h^-1 (x) = (x+2)/3

Easiest way in functions like these is to simply let y = the function (say, f(x)) and then switch x and y. Then, solve for the "new" y. The expression on the RHS will be the inverse (assuming you didn't make any assumptions implicitly such as dividing by x which could be zero, etc).

Answer 4

y= f(x) = (3/4)x so x = (4/3)y is the inverse.

y= g(x) = 3+ x so x = y-3 is the inverse

y =3x-2 so x= (y+2)/3 is the inverse.

Just solve for x in eah case.

Answer 5

x=3/4y
y=4/3x=inv of f

x=3+y
y=x-3 = inv of g

x=3y-2
y=1/3(x+2)

Answer 6

x=3/4y

x=y-3

x=(y+2)/3

Answer 7

f(x)^-1= 4/3x

g(x)^-1= x-3

y^-1: x=3y-2

y=x/3+2/3

Answer 8

y=f(x)=3/4x
4xy=3
x=3/4y

y=g(x)=3+x
x=y-3

y=3x-2
3x=y+2
x=(y+2)/3