If the perimeter of a rectangle is 26 ft and the width is 9 ft, find its length. [Hint: The perimeter of a rectangle is given by P = 2L + 2W.]
2007-08-28 05:17:37 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
26 = P = 2L + 2W
13 = L + W
13 = L + 9
4 = L
2007-08-28 05:21:41 · answer #1 · answered by Philo 7 · 0⤊ 1⤋
P=2L+2W
26=2L+2(9)
26=2L+18
2L=26-18
2L=8
L=8/2=4
L=4
2007-08-28 12:25:24 · answer #2 · answered by snehalu 3 · 0⤊ 0⤋
P = 2L + 2W = 2(L + W) = 26
L + W = 26/2 = 13 ft
L = 13 - W
Substitute the value of W = 9
L = 13 - 9 = 4
so length = 4 ft
2007-08-28 12:28:46 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋
perimeter = length + length + width +width
perimeter = 2 length + 2 width
perimeter = 2 length + (2 x 9)
26 = 2 length + 18
2 length = 26 - 18
2 length = 8
length = 8/2
thus, length = 4ft
2007-08-28 12:27:05 · answer #4 · answered by gamermic 3 · 0⤊ 0⤋
length is 8.1/2 ft, the width is 4.1/2 ft.Unless equation is wrong you can't have length shorter than width.
8ft 6 in X 4ft 6in =17ft,L+9ft,w= 26ft.
8.5x2 =17, 4.5x2 =9
17 +9 =26
EDIT-You all got the length shorter than the width, that's a first!
EDIT-you all agree that 2w+2L=P. Right?
2w=9, 26-9=17, 17devided by 2=8.5, 8.1/2..
You cannot have width longer than length.....
EDIT- YOU CANNOT HAVE WIDTH, LONGER THAN LENGTH........IN A RECTANGLE...
2007-08-28 12:26:43 · answer #5 · answered by Dragon'sFire 6 · 0⤊ 1⤋
2L + 2w = 26
2L + 2(9) = 26
2L = 26 - 18
2L = 8
L = 8/2
L = 4ft
:>:
2007-08-28 12:45:09 · answer #6 · answered by aeiou 7 · 0⤊ 0⤋
Let length be L
2L + 18 = 26
2L = 8
L = 4
Length = 4 ft
2007-08-28 13:08:28 · answer #7 · answered by Como 7 · 2⤊ 0⤋
I get L=4
2007-08-28 12:26:01 · answer #8 · answered by slinkies 6 · 0⤊ 0⤋
26=2L+2W
26=2L+2(9)
8=2L
4=L
2007-08-28 12:24:14 · answer #9 · answered by Anonymous · 0⤊ 0⤋