The three angles of a triangle add to 180 degrees.
So...
x + 2x + (2x+10) = 180
5x = 170
x = 34
Angle 1 = 34 degrees
Angle 2 = 68 degrees
Angle 3 = 78 degrees
Check: 34 + 68 + 78 = 180
2007-08-28 04:51:02
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answer #1
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answered by Mr. Scientist 4
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a + b + c = 180
where a = 1st angle, b = 2nd angle, c = 3rd angle
we also know:
b = 2a
and
c = b + 10
now you have 3 equations and 3 unknowns:
solve the 2nd eqn for a: a = (b/2)
plug a = b/2 and c = b + 10 in the first eqn:
(b/2) + b + b + 10 = 180
multiply everything by 2:
b + 2b + 2b + 20 = 360
5b = 340
b = 68 degrees
we know:
b = 2a:
68 = 2a
a = 34 degrees
c = b + 10:
c = 68 + 10 = 78 degrees.
check: 34 + 68 + 78 = 180.
ANS: a = 1st angle = 34 degrees.
2007-08-28 11:51:05
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answer #2
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answered by miggitymaggz 5
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Well, all the angles of a triangle have to add to 180 degrees. Subtract 10 and you get 170, divide by 5 and you get 34. You can check this:
Angle 1 = 34
Angle 2 = 34*2=68
Angle 3 = 68+10=78
34+68+78=180
So your answer is 34.
2007-08-28 11:53:20
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answer #3
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answered by Anonymous
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Let the 1st angle=x
the 2nd angle=2x
the 3rd angle=2x+10degrees
their sum=5x+10=180
5x=170
x=34degrees ANS
2007-08-28 11:52:55
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answer #4
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answered by Anonymous
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Let "a" be the "first" angle. Use the fact from geometry that the sum of the angles in any triangle is always 180 degrees.
That means:
(first angle) + (second angle) + (third angle) = 180
or:
(a) + (2a) + (2a+10) = 180
Now just solve for "a".
2007-08-28 11:53:00
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answer #5
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answered by RickB 7
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let x be 1st angle, 2nd is 2x, 3rd is 2x+10, and all 3 add up to 180, so
x + 2x + 2x+10 = 180
5x = 170
x = 34
2x = 68
2x+10 = 78
2007-08-28 11:51:22
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answer #6
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answered by Philo 7
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x + 2x + 2x + 10 = 180
5x + 10 = 180
5x = 170
x = 34
Angle 1 = 34
Angle 2 = 68
Angle 3 = 78
2007-08-28 11:50:45
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answer #7
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answered by dEE 2
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angles called A, B, and C
A + B + C = 180
B = 2A
C = B + 10 = 2A + 10
A + B + C = 180
A + (2A) + (2A+10) = 180
A + 2A + 2A +10 = 180
5A + 10 = 180
5A = 170
A = 170 / 5
A = 34
2007-08-28 11:52:05
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answer #8
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answered by Anonymous
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