A box has:
volume = (x² + 5x + 6)(x + 5)
height = x + 2
find the area of the bottom of the box
2007-08-28 04:19:01 · 4 answers · asked by rainwater 3 in Science & Mathematics ➔ Mathematics
V = (x + 3) (x + 2) (x + 5)
h = (x + 2)
A = (x + 3) (x + 5)
Area of bottom = (x + 3) (x + 5) units ²
2007-08-28 04:32:45 · answer #1 · answered by Como 7 · 2⤊ 0⤋
The volume of a box is = length x width x height
Volume = (x+2)(x+3)(x+5), factored.
We know that height is (x + 2)
So, the area of bottom is (x+3)(x+5) = x^2+8x+15.
This is the correct answer by the way... the others are incorrect.
2007-08-28 04:28:03 · answer #2 · answered by kvolcom13 3 · 0⤊ 1⤋
the volume of a box is = lwh
(x+2)(x+3)(x+5)
height is x + 2
so the area of bottom is (x+3)(x+5) = x^2+8x+15
2007-08-28 04:22:55 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Volume Vof the rectangular box=(x^2+5x+6)(x+5)
=(x+2)(x+3)(x+5)
Heighth=x+2
Area of the base=V/h
=(x+3)(x+5).
x^2+8x+15.ANS.
2007-08-28 04:27:54 · answer #4 · answered by Anonymous · 0⤊ 1⤋