2007-08-28 03:58:02 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x+y=54
x-y=8
x=8+y
8+2y=54
2y=46
y=23, x=31
2007-08-28 04:04:05 · answer #1 · answered by de4th 4 · 0⤊ 0⤋
The numbers are 23 &31
2007-08-28 11:23:56 · answer #2 · answered by pran 1 · 0⤊ 1⤋
Make an equation:
x + (x-8) = 54
2x - 8 = 54
+8 = +8
2x = 62
/2 = /2
x = 31 so x-8 = 31 - 8 = 23
the numbers are 31 and 23
2007-08-28 11:05:49 · answer #3 · answered by MnM23 2 · 0⤊ 0⤋
23 and 31. 31-23=8. 31+23=54
2007-08-28 11:03:50 · answer #4 · answered by insanity1990 2 · 0⤊ 0⤋
23 and 31
2007-08-28 11:03:27 · answer #5 · answered by metz 2 · 0⤊ 0⤋
23 and 31
something +(something +8)=54
subtract 8 from both sides
2 of something =46
divide by 2
1st something is equal to 23 and the second one adds 8 therefore it is 31, check by adding 23 and 31 and sure enough you get 54
2007-08-28 11:05:27 · answer #6 · answered by David G 3 · 0⤊ 0⤋
23; 31
2007-08-28 11:06:20 · answer #7 · answered by JC 2 · 0⤊ 0⤋
23 and 31.
How I found it=
54-8=46
46/2=23
23+8=31
23+31=54
2007-08-28 11:04:52 · answer #8 · answered by jannabanana 4 · 0⤊ 0⤋
Let numbers be x and y
x + y = 54
x - y = 8----ADD
2x = 62
x = 31
y = 23
Numbers are 31 and 23
2007-08-28 11:09:30 · answer #9 · answered by Como 7 · 1⤊ 0⤋
let's say one number is x
second one is x+8
x+x+8 = 54
2x=46
x=23
x+8 = 31
2007-08-28 11:03:43 · answer #10 · answered by Anonymous · 0⤊ 0⤋