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(2x^2)^3 (4x^3)^-1 and (3x^-2)(3x^2/2)^2

2007-08-28 03:20:34 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

Expression 1
8 (x^6) / 4 ( x ³ )
2 x ³

Expression 2
(3/x²)(9x^4) / 4
27 x^4 / (4 x ²)
(27/4) x ²

2007-08-28 04:48:20 · answer #1 · answered by Como 7 · 2 0

(2x^2)^3 (4x^3)^-1
= 2x × 2x × 2x / 4 × x × x × x
= 2 x / x
= 2

(3x^-2)(3x^2/2)^2
= [3 / (x × x)] × [(3 x ^2× 3x^2)/ 2 × 2]
=3 × 3 × 3x^2 / 2 × 2
= 27x^2/4

2007-08-29 07:39:43 · answer #2 · answered by Pranil 7 · 0 1

8x^6/4x^3 = 2x^3

(3/x^2)(9x^4/4) = 27x^2/4

2007-08-28 10:34:21 · answer #3 · answered by John V 6 · 0 0

I have decided that for now on, when people post more then one problem and/or ask the question directly out of the book. I will no long answer them.

2007-08-28 10:36:43 · answer #4 · answered by Xash 3 · 0 0

Ah the old using Yahoo Answers to your homework trick :P

2007-08-28 10:28:10 · answer #5 · answered by 4 Horsemen 4 Life 2 · 0 0

(2x^2)^3(4x^3)^-1=8x^6/4x^3=2x^3

(3x^-2)(3x^2/2)^2=(3/x^2)(9x^4/4)=(27x^2)/4

2007-08-28 10:39:52 · answer #6 · answered by XA 1 · 0 0

144^ and 36^

2007-08-28 10:40:10 · answer #7 · answered by Anonymous · 0 0

easy

2007-08-29 12:38:55 · answer #8 · answered by Anonymous · 0 0

?????????

2007-08-29 07:07:56 · answer #9 · answered by Kriti 2 · 0 1

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