torque = force * perpendicular distance
so if you have a square that rotates about an axis that is not in the centre of the square, and a force is applied to one corner of the square an it is perpendicular to the square, does this still constitute torque.
|--------------------|
|--------------------|
|--------------------|
|----o =Axis------|
|--------------------|
|--------------------|<-------- Force Applied here
2007-08-28
00:03:20
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3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Physics