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I havent done this in forever and its killing me that I dont remember.

Say you have an equation -3y=5x+6
When you divide the 5 and 6 by 3...would you leave the 3 negative or make it positive??

Thanks!!

2007-08-27 20:24:33 · 10 answers · asked by babeegurl494 2 in Science & Mathematics Mathematics

10 answers

-3y = 5x + 6
X by - 1
3y = - 5x - 6
Divide by 3
y = (- 5 / 3) x - 2

2007-08-27 21:54:00 · answer #1 · answered by Como 7 · 2 0

I do not understand the question . This is some subjestion
1) If simplify the equation by 3 the answer will be
-y=(5/3)x+2 or y+(5/3)x=-2
2)if simplify by 2
(3/2)y+ (5/2)x =-3
3) If simplify by 6
(1/2)y + (5/6)x =-1
I hope you get the idea from there......good luck

2007-08-27 20:38:11 · answer #2 · answered by JQ 1 · 0 0

You treat everything in the equation the same way. If you multiply by 5, you multiply everything by +5. If you subtract 3, you subtract 3 from every term. Starting with -3y = 5x+ 6, multiply everything by -1/3 to get y = -5x/3 - 2.

2007-08-27 20:32:43 · answer #3 · answered by Anonymous · 0 0

Its up to you whether you want to divide it by 3 or -3.
If you only divide it by 3, no other symbols or whatsoever, you don't need to care about the negative,
-3y = 5x + 6
-y = 5/3 x + 2
y = -5/3 x - 2
In most case I would recommend you divide it by -3 as it is a faster method.

2007-08-27 22:33:12 · answer #4 · answered by 痴心情长剑 3 · 0 1

If you divide 5 and 6 in the right hand side of the equation by 3 then the 3 in the left hand side will remain negative as it is.

-3y=5x+6
or, -y=5x/3+6/3


If you divide 5 and 6 in the right hand side of the equation by (-3) then the 3 in the left hand side will become positive.

-3y=5x+6
or, y= -5x/3-6/3

2007-08-27 20:38:36 · answer #5 · answered by defeNder 3 · 0 0

This is the equation of a straight line. The general form of the equation of a straight line is:

y = mx + c

You see the coefficient of "y" is 1.

So, you need to make the co-efficient of "y" 1 in the given equation. Therefore, divide the given equation by -3 that yields:

y = -(5/3)x - 2

2007-08-27 20:30:06 · answer #6 · answered by seminewton 3 · 0 0

What do you want to do? To find the value of "y" in terms of x
or to find the value of "x" in terms of y ?
Anyway I will do both.
-3y=5x+6
y . .= (5x+6)/-3 = (-5/3)x -6/3 = (-5/3)x-2, if the +ve quantities are devided by -ve quantities the result will be -ve.
y=(-5/3)x-2 . . . . . . . Ans.
===========

Again,
-3y=5x+6
-3y-6=5x
5x= -(3y+6),if we are giving -ve sign outside the brackets the signs of the terms inside the brackets should be changed.
x= -(3y+6) / 5 . . . . .Ans.
===========

2007-08-27 20:43:20 · answer #7 · answered by Joymash 6 · 0 0

-3y=5x+6
y = (-3/5)x - 6/3
= -3x/5 - 2

or
-3y=5x+6
-y = (3/5)x + 6/3
= 3x/5 + 2

2007-08-27 20:29:06 · answer #8 · answered by Anonymous · 0 0

its ur wish
suppose u leave the minus sign as it is. then ur equation will look like this

-y = 5/3 x+6/3


and if take the minus sign to right hand side your euation will look like this

y = -5/3 x -6/3

both equations are correct

2007-08-27 20:27:18 · answer #9 · answered by mubaris h 3 · 0 0

no, infact divide by -3
then you get y= -5/3 x + 2

2007-08-27 20:31:15 · answer #10 · answered by s_javeds 1 · 0 0

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