ok so I have to find the remaining 5 functions, I am given sin = (sq root 3) / 4
so a^2 +b^2 = c^2
a^2 + sq root 3^2 = 4^2
a^2 + 3 = 16
a = sq root 13
cos = sq root 13 / 4
tan = sq root 3 / sq root 13
csc = 4 / sq root 3
sec = 4 / sq root 13
cot = sq root 13 / sq root 3
did I do this correctly??
please help / explain if I didn't . . . thanks!!
2007-08-27 17:28:49 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You could have just used the fact that sin^2(x) + cos^2(x) = 1 to find cos(x), then the defintions of the other trig functions from there. But that works too.
2007-08-27 17:35:01 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Yes you have done it correctly. The only thing you need to do now is make sure that it is a correct fraction. By that I mean that the denominator only consists of an integer.
To do that you just need to multiply the fraction by the denominator's multiple of 1:
4 / sq root 3 =
4 / sq root 3 * sq root 3/sq root 3 =
(4 sq root 3) / 3
2007-08-28 00:36:32 · answer #2 · answered by AibohphobiA 4 · 1⤊ 0⤋
They all look good to me.
2007-08-28 00:35:26 · answer #3 · answered by Helmut 7 · 0⤊ 1⤋