2007-08-27 15:31:58 · 19 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
I actually saw someone with that name on their mailbox 2 towns over....
2007-08-27 15:35:06 · update #1
the movie is called Mr. Woodcock
heres a link to the internet movie database site for it...
http://imdb.com/title/tt0419984/
2007-08-27 15:37:16 · update #2
I think they probably already get picked on!
2007-08-27 15:35:13 · answer #1 · answered by ~SheSul~ 6 · 0⤊ 0⤋
Woodcock is a pretty English name. But you presume the Cherokee lineage is through your grandfather and not your grandmother. You might want to go back a few generations on both lines of the family and see what you find. Preconceived ends are a killer in genealogy.
2016-04-02 02:44:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Kinda the same situation with people who are named "Hermione" or "Napoleon" and get picked on for famous movies. I mean, they didn't choose their name. But yes, I think the movie will add to humility.
2007-08-27 15:35:34 · answer #3 · answered by mikeg1992 3 · 0⤊ 0⤋
Yes
2007-08-27 15:34:56 · answer #4 · answered by rudolph228 2 · 0⤊ 0⤋
Probably. I used to know someone named Lisa Simpson, and she gained a bit of celebrity status among her peers as a result.
2007-08-27 15:35:48 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I think they get picked on already. I saw a file that had a last name of Glasscock and I could not contain myself.
2007-08-27 15:36:30 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I think if they already don't get picked on, some close friends might say something joking about it, but Nothing major no.
2007-08-27 15:37:45 · answer #7 · answered by Special K 2 · 0⤊ 0⤋
They won't get picked on by mature people. What's in a name anyway?
2007-08-27 15:34:53 · answer #8 · answered by robee 7 · 0⤊ 0⤋
I wish that was my last name Cooper is so boring to have as a last name.
2007-08-27 18:40:07 · answer #9 · answered by Steven C 7 · 0⤊ 0⤋
Not by anyone named splinterlip.
2007-08-27 15:36:01 · answer #10 · answered by ropar 5 · 0⤊ 0⤋