please help me
2007-08-27 15:24:50 · 5 answers · asked by victoria 1 in Science & Mathematics ➔ Mathematics
-3y + 3^2 = -7
-3y + 9 = -7
-3y = -16
y = 16/3.
2007-08-27 15:30:01 · answer #1 · answered by Anonymous · 1⤊ 0⤋
If --3y + 3^2 = --7
then --3y + 9 = --7
=> --3y = --16
=> y = 16/3
2007-08-27 22:37:55 · answer #2 · answered by sv 7 · 0⤊ 0⤋
-3y+3 squared=7
-3y+9-9=-7-9
-3y=-16
-3y/-3=-16/-3
y=5 1/3
2007-08-27 22:43:29 · answer #3 · answered by Max 6 · 0⤊ 0⤋
(-3y +3)^2 = -7
(-3y + 3)(-3y + 3) = -7
9y^2 -9y -9y +9 = -7
9y^2 -18y +9 = -7
9y^2 - 18y +9 + 7 = -7 +7 = 0
9y^2 -18y + 16 = 0
This is a quadratic in standard form.
ax^2 + bx + c = 0
where
a = 9
b= -18
c = 16
and where the solution is found with
y = [-b +/- SQRT( b^2 - 4ac)] / 2a
2007-08-27 22:33:02 · answer #4 · answered by Raymond 7 · 0⤊ 0⤋
GI's answer is right
2007-08-27 23:05:59 · answer #5 · answered by Anonymous · 0⤊ 0⤋