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y - 2 = -2x
3y - 2 = -6x

how do i solve this ?

2007-08-27 11:19:56 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

y - 2 = -2x
3y - 2 = -6x
then
y = -2x +2 so its slope is = -2
3y = -6x +2
y = -2x + 2/3, so its slope is = -2
therefore the 2 lines are parallel

2007-08-31 07:06:24 · answer #1 · answered by robert 6 · 0 0

Hi,
If lines have the same slope, they are parallel. So, one way to determine if they have the same slope if to put the equations in slope-intercept form. That's
y = mx +b (Where m is the slope and b is they y-intercept.)
So, let's put the equations in slope-intercept form.
First one:
y-2 = -2x
y = -2x +2 (Add 2 to both sides of the equation.)

Second one:
3y-2 = -6x
3y = -6x +2 (Add 2 to both sides.)
y = -2x + 1/3 (Divide each term by 3.)
So, m is the same for both equations and, therefore, they are parallel. We don't care what the intercept is.


Hope this helps.
FE

2007-08-27 12:00:04 · answer #2 · answered by formeng 6 · 0 0

if they are parallel, then the slope is the same

so, first put equations in generic format y = mx+b

1) y = -2x+2

2. 3y = -6x + 2 Divide by 3 y=-2x + 2/3

slopes are both -2; so lines are parallel

2007-08-27 11:39:43 · answer #3 · answered by Maverick 7 · 0 0

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