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16) Fe2O3 + H2 ----> Fe +H2O
17) PbO2 + CO ----> Pb + CO2
18) Al + Fe2O3 ----> Fe + Al2O3
19) Fe3O4 + C ----> Fe + CO2
20) H20 + Co ----> H2 + CO2

can anyone help solve balancing these equations, i'm really confused. Very apreciated :D

2007-08-27 11:03:23 · 3 answers · asked by **Lilyanne** 3 in Science & Mathematics Chemistry

3 answers

Are you confused because you weren't paying attention in class? Or because you haven't done the reading yet? lol
These are simple questions, and I'll explain how to do the first two, but then you'll have to do the rest yourself :)

Write down the elements used and then underneath write down how many atoms of each element you have on that side.

Fe-2 : Fe-1
O-3 : O-1
H-2 : H-2

you see you need to double the Fe on the right, and triple the O on the right, but when you triple the O, you also triple the H! so go back and triple the H on the other side

Fe203 + 3H2 ---> 2Fe + 3H2O

Pb-1 : Pb-1
O - 3 : O - 2
C - 1 : C - 1

now here you have O in both molecules on the left, so by simply doubling the CO on the left and doubling the CO2 on the right, you will balance it with 2 C and 4 O on each side

PbO2 + 2CO ---> Pb + 2CO2

2007-08-27 11:51:55 · answer #1 · answered by Matt S 2 · 0 0

Fe2O3 + 3 H2 = 2 Fe + 3 H2O
PbO2 + 2 CO = Pb + 2 CO2
Al + Fe2O3 = Fe + Al2O3
Fe3O4 + 2 C = 3 Fe + 2 CO2
H2O + CO = H2 + CO2

2007-08-27 12:36:59 · answer #2 · answered by Perger, T. 1 · 0 0

Gee! you know, If these were difficult eq. ... but these are some of the simpler equations you can find!. C'mon, you can solve them, there are several methods

2007-08-27 11:11:36 · answer #3 · answered by Manuelon 4 · 1 0

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