determine the grams of ethylene glycol(c2h4(oh)2) which must be dissolved in 2500 g of water to make a 4.78 m solution
2007-08-27 09:34:31 · 5 answers · asked by louis h 1 in Science & Mathematics ➔ Chemistry
m = (weight of solute* 1000)/ (MW of solute*weight of solvent)
weight of solute = m *MW of solute * weight of solvent /1000
= 4.78 * 62*2500/1000
= 740.9 grams
2007-08-27 09:48:47 · answer #1 · answered by ADITYA V 3 · 0⤊ 0⤋
1. Figure out molecular weight. (These are approximate)
2 * carbon (mw 12) + 4 * hydrogen (mw 1) + 2 * oxygen (mw 16) + 2 * hydrogen (mw 1)
=24 + 4+ 32 + 2 = 62.
That means it weighs ~62 grams per mol. A 1 molar solution will have 62 grams in 1 liter of water (which is 1000g of water).
For 4.78M, it's 62 * 4.78 to make 1 liter of a 4.78M solution. Then multiply by 2.5 since you are making 2.5 liters of it.
Grand totay 4.78 * 62 * 2.5 = ~740.9 grams.
2007-08-27 09:49:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Be careful with some of the previous answer. Be certain that you know that you are dealing with molality (m) (moles of solute per kilogram of solvent) rather than molarity (M) (moles of solute per liter of solution).
For dilute solutions in water, they are quite similar, but become very different for concentrated solution and solutions made in solvents other than water.
2007-08-27 09:56:36 · answer #3 · answered by hcbiochem 7 · 0⤊ 0⤋
in accordance to textual content cloth e book it rather is AL
2016-12-31 06:43:41
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answer #4
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answered by ? 3
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m solutions are g solute per 1000g solvent
so you want 4.78g/1000g for 2500g
4.78*2.5=your answer
2007-08-27 09:44:53 · answer #5 · answered by billgoats79 5 · 0⤊ 1⤋