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I need to evaluate the following indefinite integral:

x(x^2+3)^(1/2)

I first thought of trying integration by parts, but I think I'm supposed to use substitution. However, all my examples have a definite integral. So what do I do?

2007-08-27 09:33:36 · 3 answers · asked by psimons144 1 in Science & Mathematics Mathematics

3 answers

I = ∫ (x) (x² + 3)^(1/2) dx
Let u = x² + 3
du = 2x dx
du / 2 = x dx
I = (1/2) ∫ u^(1/2) du
I = (1/2) u^(3/2) / (3/2) + C
I = (1/3) (x² + 3)^(3/2) + C

2007-08-31 01:11:15 · answer #1 · answered by Como 7 · 1 0

First of all, integration by substitution can be used for both definite and non-definite integrals.
x(x^2+3)^1/2
let x^2+3 = t
2xdx = dt
x dx = (1/2)dt
the given integral becomes
(1/2) integ sqrt(t) dt
(1/2)t^(1/2+1)/(1/2+1)
=(1/2)t^(3/2)/(3/2)
=(1/3)t^3/2
=(1/3)(x^2+3)^(3/2)+C

2007-08-27 09:48:14 · answer #2 · answered by cidyah 7 · 0 0

Let u = x^2+3
Then du/2 = xdx
So 1/2 integral u^1/2 du = (1/2)(2/3) u^3/2= 1/3(x^2+3)^3/2+C

2007-08-27 09:48:44 · answer #3 · answered by ironduke8159 7 · 2 0

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