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the (9+13) is over 6 in parenthesis

2007-08-27 08:40:17 · 5 answers · asked by Diana K 1 in Science & Mathematics Mathematics

5 answers

If the problem is 3(9+13)/6 first add 9 and 13 to get 22 multiply this by 3 to get 66 and divide that by 6 to get 11.

If the problem is 3((9+13)/6) then you first add 9 and 13 to get 22 divide by 6 to get 3.66667 and multiply by 3 to get 11.

2007-08-27 08:50:03 · answer #1 · answered by shomelon 2 · 0 0

Use the order of operations:

Please (parenthesis)
Excuse (Exponents)
My Dear (Multiplication and Division)
Aunt Sally (Addition and Subtraction)

So here you want to do the parenthesis first (9+13) = 22. Which leaves you with:

3*22/6

Now, because multiplication and division are on the same line above (My Dear), it doesn't matter what order you do it in. Since 22 is not divisible by 6, it's easier to multiply first:

3*22 = 66

and

66/6 = 11

If you had divided first, you'd have

(22/6)*3...the three cancels out, and you're left with

22/2 = 11 (same answer)

you can also look at it as:

(3/6)*22 = (1/2)*22 = 22/2 = 11

2007-08-27 15:52:25 · answer #2 · answered by Matics101 6 · 0 0

3(N9+13/6
=22/2
=11 ANS

2007-08-27 15:54:38 · answer #3 · answered by Anonymous · 0 0

3(9 + 13) / 6 =

3(22) / 6 =

66 / 6 =

11

- - - - - - - s-

2007-08-27 15:52:06 · answer #4 · answered by SAMUEL D 7 · 0 0

You just factor out and divide by 6...
3(9+13)/6
27+39/6
66/6
11(ans.)

2007-08-27 16:05:19 · answer #5 · answered by bowleggedgirl 1 · 0 0

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