The Earth rotates eastward at speed s=500m/s at equator. Airplane flies in due west direction along equator at speed v=s=500m/s wrt earth.
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When I do this problem in the frame of refence rotating with the earth, then:
forces acting on the plane are:
gravity mg (downwards)
centrifugal force mω²R = ms²/R (upwards)
airlift F (upwards)
dynamic equation for the airplane is
ma = F - mg + ms²/R
Accleration a is centripetal accleration:
a = -v²/R (minus signifies downward direction)
Final equation for airlift:
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F = m(g - 2s²/R)
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But when I consider this problem in inertial frame of reference, the airplane is at rest, and I get simply
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F = mg
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2007-08-27
07:18:39
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4 answers
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asked by
Alexander
6
in
Science & Mathematics
➔ Physics