Math help please.?

Question

Can you work this out please and show how you do it so I can learn? My professor dosn't give us any examples. Thanks!
Find the slope.
-3x + 2y=6

Answer 1

the easiest way to spot the slope is writing the eqn in slope-intercept form: y = mx + b where m is the slope and b is the y-intercept.

so, put this equation in that form:

first, add 3x to both sides:

2y = 3x + 6

now divide both sides by 2:

y = (3/2)x + 3

therefore, m = (3/2) and b = 3

slope = 3/2

Answer 2

-3x + 2y=6
+ 2y= 3x+6
y = 3/2 x + 6/2
y = mx + c

=> slope = 3/2

Answer 3

You rearrange the formula to cast it as y = mx+c, where m and c are constants to be determined. m will be the slope. In this case, we have 2y = 6 + 3x, or y = 3x/2 + 3, so the slope is 3/2.

Answer 4

-3x + 2y = 6

or, 2y = 3x + 6
or, y = (3/2)x + 3

now the general equation of straightline is y = mx + c, where m = slope of the straightline

if these two equations are compared very carefully then u will surely find that m = 3/2 & c = 3

here we know that m = slope of that straightline

so, the slope of the given straightline will be 3/2 [ans]

Answer 5

- 3x + 3y = 6

Transpose 3x

- 3x + 2y + 3x = 3x + 6

2y = 3x + 6

Divide both sides of the equation by 2

2y / 2 = 3x / 2 + 6 / 2

y = 3/2x + 3

- - - - -
The slope is 3/2

- - - - - - s-

Answer 6

In standard linear form
Ax + By = C,
m = -A / B.

In your problem,
m = -(-3) / 2
m = 3 / 2.