im confused, please help?

Question

the equation is 2/x+3/y and the directions say "please perform the indicated operations. leave all answers with positive exponents.

what am i supposed to do?

Answer 1

my guess is, you need to find a common denominator:

(2/x)(y/y) = (2y/xy)

(3/y)(x/x) = (3x/xy)

Now add the two = (3x + 2y)/(xy)

Everything has positive exponents (namely: +1), so you are done.

(Note: there ARE exponents involved but they are +1, which you don't typically write. If the directions said to write everything without a variable in the denominator, you would write as: 2x^-1 + 3y^-1.)

Answer 2

Perhaps here something is missing. In case of any equation there must have one left hand side term & one right hand side term , for example, A + B = C + D. Here A+B is the left hand side term & C+D is the right hand side term.
But in ur question there is no RHS term or LHS term(if this is considered as the RHS term)
so, plz check ur question again very carefully.

But, ur given term can be factorised as below,

2/x + 3/y
= (2y + 3x) / xy

Answer 3

I'm confused too.

"2/x+3/y" is not an equation.

If you don't know the values of x or y, there aren't really any "indicated operations" to perform (unless this is an exercise in adding fractions?)

There aren't any exponents involved.

Are you sure you gave this to us exactly the way it's written down?

Answer 4

2/x+3/y = (2y+3x)/xy

so i think thats the answer.