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3 answers

Because a positive test for secondary amines (R2NH) is formation of a white solid that is insoluble in aqueous alkali.

C6H5-SO2Cl + R2NH ===> C6H5-SO2NR2(s)

But if the amine is somehow amphoteric in the first place (soluble in both acids and bases), then the benzenesulfonamide will be anomalously soluble in alkali also.

2007-08-27 06:58:55 · answer #1 · answered by steve_geo1 7 · 0 0

Amphoteric amines give erroneous results. It could be from solubility or a lack of reactivity.

2007-08-27 05:39:22 · answer #2 · answered by drochem 5 · 0 0

solubility or lack of reactivity.

2007-08-27 06:49:49 · answer #3 · answered by jessica c 3 · 0 0

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