methylated spirits. this is the information I know
Mass of empty cup: 2.2g (±0.05g)
Mass of cup with methylated spirits: 49.5g (±0.05g)
Mass of heated water: 44.8g (±0.05g)
Volume water: 50ml (±0.05ml)
Original temperature of methylated spirits: 20.0º (±0.5º)
Temperature of heated water: 80.0º (±0.5º)
Temperature of mixture: 54.0 º (±0.5º)
Specific Heat Capacity of a Mixture: MwaterCwaterΔTwater=MmethCmethΔTmeth
Assume specific heat capacity if water is 4.19 x 103 J/Kg-1K-1
i can solve the problem but i dont know how to take into account the the uncertanties to get relative uncertainty and percentage discrepency
2007-08-27 02:11:37 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The problem is not correct. If the mass of heated water is 44.8g(+-0.05g). The max is 44.85g. The volume of water 50ml(+-0.05ml). The min is 49.95ml. The density of water at 80degree is 0.971g/ml, which you may find in any literature. Therefore, 49.95* 0.971 = 48(g), far higher than 44.85g.
Where did you get this wrong problem?
2007-08-27 12:19:35 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋