If possible please show necessary working, thankyou much so!
2007-08-26 23:36:40 · 9 answers · asked by ♥Xenia♥ 5 in Science & Mathematics ➔ Mathematics
x^2 + 5 = 6x
x^2 - 6x + 5 = 0
(x - 5)(x - 1) = 0
x - 5 = 0 or x - 1 = 0
x = 5 or x = 1
2007-08-26 23:54:36 · answer #1 · answered by Anonymous · 1⤊ 0⤋
X^2+5= 6x as
by factorizing
= X^2--6X + 5 = X^2 - 5X - X +5 =0
= X ( X - 5) - 1( X- 5) =0
= (X-1) (X-5) =0
we conclude that
if (x -1) (x-5) =
this shows that X=1 and X= 5
these are the two values of the X
2007-08-26 23:56:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a million. D 2. D 3. D 4. B 5. D 6. B 7. B 8. D 9. D 10. D eleven. D 12. C thirteen. A 14. C 15. B sixteen. A 17. a million=B, 2=A, 3=D, 4=C 18. B 19. a million=B, 2=A, 3=D, 4=C 20. C 21. A 22. D 23. C 24. C 25. B
2016-12-16 06:04:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x^2 + 5 = 6x Subtract 6x from each side:
x^2 - 6x +5 = 0 Now factorise it:
{x - 5}{x - 1} = 0 , so,
x - 5 = 0, OR, x -1 = 0, so,
x = 5, OR x = 1. Hope this helps, Twiggy.
2007-08-26 23:46:00 · answer #4 · answered by Twiggy 7 · 0⤊ 0⤋
x^2 + 5 = 6x
=> x^2 -- 6x + 5 = 0
=> x^2 -- 5x -- x + 5 = 0
=> x(x -- 5) -- 1(x -- 5) = 0
=> (x -- 5)(x -- 1) = 0
when x -- 5 = 0 => x = 5
when x -- 1 = 0 => x = 1.
Solution is x = 5, 1.
2007-08-26 23:45:16 · answer #5 · answered by sv 7 · 0⤊ 0⤋
x^2 - 6x + 5 = 0
solving this quadratic equation :
x^2 - 5x - x + 5 = 0
x ( x - 5 ) - 1 ( x - 5 ) = 0
(x - 5) ( x - 1 ) = 0
x = 5 or x = 1
2007-08-26 23:46:53 · answer #6 · answered by dren 3 · 0⤊ 0⤋
x² - 6x + 5 = 0
(x - 5) (x - 1) = 0
x = 5 , x = 1
2007-08-27 06:58:08 · answer #7 · answered by Como 7 · 0⤊ 0⤋
x^2 - 6x + 5= 0
(x-5)(x-1)= 0
therefore x = 5 or 1
hope that helps! :)
2007-08-26 23:42:53 · answer #8 · answered by brydiem 2 · 0⤊ 1⤋
x ^2 - 6x +5 = 0
x1,2 = (6 +/- sqrt ( 36 - 4 * 1 * 5 ))/2
x1,2 = (6 +/- sqrt (16))/2
x1,2 = (6 +/- 4)/2
x1= 5
x2= 1
2007-08-26 23:42:33 · answer #9 · answered by ivana :) 1 · 0⤊ 1⤋