x^2 + y^2 + z^2 + 4x - 2y + 4z + 5 = 0 and x^2 + y^2 + z^2 = 4. Can anyone help me determine the equation for the intersection of these 2 spheres??
2007-08-26 19:09:03 · 2 answers · asked by Robert W 1 in Science & Mathematics ➔ Mathematics
Wouldn't be that set of points that satisfy:
x^2 + y^2 + z^2 +4x -2y +4z +5 = x^2 +y^2 +z^2-4
(setting the equations for each sphere equal to each other)
4x -2y+4z +9 = 0
2007-08-26 19:14:54 · answer #1 · answered by VampireDog 6 · 0⤊ 1⤋
x^2+y^2+z^2 +4x-2y+4z+5 = x^2+y^2+z^2-4
so 4x-2y+4z+9=0 (this is the equation of a `plane)
Now intercept this plane with one of the spheres
x^2+y^2+(2y-4x-9)^2/16-4=0 and develop
This equation with the one of the `plane gives you the equation you are looking for which represents a circumference in this plane
2007-08-27 10:33:27 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋