Simplifying expressions?

Question

I've already asked an algebra question just about five minutes ago, but i've encountered yet another difficult problem..so helP?

the problem is about simplifying algebraic fractions:
[(2) / (x-3)] * [(2x-6) / (8(x+4))]


Thanks

Answer 1

2(2x - 6)
------------
(x - 3) * 8(x + 4)


4x - 12
----------
(x - 3)(8x + 32)

4(x-3)
---------
(x-3)(8x + 32)

4
-----------
8x + 32



1
--------
2x + 8


1
---------
2(x + 4)

Answer 2

2/(x-3) * 2(x-3)/[8(x+4)]
the 2 2 & 8 reduce to 1 & 2 and the (x-3) cancel each other leaving:

1/[2(x+4)]

Answer 3

[ 2 / (x-3) ] * [ (2x - 6) / (8x + 32) ]

[ 2 * (2x - 6) ] / [ (x - 3) * (8x + 32) ]

[ 4x - 12 ] / [ 4 * (x - 3) * (2x + 8) ]

[ 4 * (x - 3) ] / [ 4 * (x - 3) * (2x + 8) ]

1 / (2x + 8)