12
2007-08-26
16:15:54
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6 answers
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asked by
Kevin P
1
in
Science & Mathematics
➔ Mathematics
21-9 < x < 21+9
i.e. 12 < x < 30.
2007-08-26 16:18:11 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 1⤋
Make 9 & 21 sides next to each other with angle t,
so 0 < t < 180 degreees, when the 3rd side L would be
21-9 < L < 21+9
12 < L <30
2007-08-26 23:22:03 · answer #2 · answered by vlee1225 6 · 0⤊ 1⤋
12
The solution can be found by imagining the two sides at 0 degrees (so the third side is 21-9=12) or at 180 degrees ( so 21+9=30).
.
2007-08-26 23:20:59 · answer #3 · answered by tsr21 6 · 1⤊ 0⤋
The lower limit will be 21-9 = 12, and the upper limit will be 21+9 = 30. So the first choice is correct.
2007-08-26 23:19:17 · answer #4 · answered by Anonymous · 0⤊ 1⤋
this is a hypotenuse thingy the rule states that the longest side is the square root of the sum of the squares of the two adjacent sides. so-assuming that these are two adjacent sides the third side would be 23. 23 being a square root of the sum of 21 square and 9 square.
2007-08-26 23:26:55 · answer #5 · answered by exnav138 4 · 0⤊ 1⤋
this is a problem of triangle inequality, just subtract the two sides that will be the least measure, add them the maximum measurement.
12 < x < 30
2007-08-26 23:22:58 · answer #6 · answered by rochelle 2 · 1⤊ 0⤋