how do you do these math problems??? please help :(?

Question

3x<2x-3 U 7x>4x-9

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-2k + 8 < 14 U 3k + 1<1


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PLEASE HELP ME IM SO STUMPED AND I KEEP GETTING THE WRONG ANSWER :(((

U stands for union

Answer 1

Hi,

3x<2x-3 U 7x>4x-9
Solve for x on both inequalities.
3x<2x-3
x<-3

7x>4x-9
3x>-9
x>-3

If you are looking for x<-3 U x>-3, you are looking for numbers that are less than -3 and at the same time also greater than -3. there are no numbers for which this is true, so this problem is a NO SOLUTION or Ø !!
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-2k + 8 < 14 U 3k + 1<1
Solve for k on both inequalities.
-2k + 8 < 14
-2k < 6
k > -3

3k + 1 < 1
3k < 0
k < 0

If you are looking for where k > -3 and k < 0, then -3 < k < 0.

<--¤=====¤----------->
....-3.-2.-1.0

This is hollow dots at -3 and 0 with shading in between.

I hope that helps!! :-)

Answer 2

3x < 2x+3 ∪ 7x > 4x-9

The first step in each case is to group all your x terms on the same side. Remember that when you take a term from one side to the other, you have to change it from positive to negative or from negative to positive. So we get:

3x - 2x < 3 ∪ 7x - 4x > -9
Simplifying the x terms gives us
x < 3 ∪ 3x > -9
Divide the second expression by 3 to get
x < 3 ∪ x > -3.
So everything to the left of 3 is included, as well as everything to the right of -3. Since -3 is less than 3, this means the whole number line is included.


-2k + 8 < 14 ∪ 3k + 1 < 1

Again, put the variable (k) terms on one side and the numbers on the other. This time it's the number terms we have to move. The same rule applies about changing the sign:

-2k < 14 - 8 ∪ 3k < 1 - 1
so we get
-2k < 6 ∪ 3k < 0
Now we divide by -2 on the first half and 3 on the second half. Remember that when you divide an inequality by a negative number, the inequality changes direction. So we get
k > -3 ∪ k < 0

So everything to the right of -3 and everything to the left of 0 will be included. Again, since -3 < 0 this will be the whole number line.

Answer 3

3x<2x-3 U 7x>4x-9
x < -3 U 3x > -9
x < -3 U x > -3

-2k + 8 < 14 U 3k + 1<1
-2k < 6 U 3k < 0
k > -3 U k < 0

Answer 4

3x<2x-3 U 7x>4x-9

Well, it's not clear waht U is.
But if you have
3x<2x-3
then
x<-3 (by subtracting 2x from both sides)

If you have
7x>4x-9
then
3x < -9
or x <-3

-2k + 8 < 14
then
-2k < 6
so
2k > -6
so k > -3

3k + 1<1
so 3k < 0
so k < 0
.

Answer 5

2 pts

Answer 6

Thats a very good question but im only going into 7th grade so i couldent easily tell u.

Answer 7

their kinda hard im 12 and i know how to but if i were right there 2 explain 2 u i would um email me [e-mail] , and ill give y atips
thx -
macey

Answer 8

wat is U?