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Eliminate the parameter and write a rectangular equation for:

x=t^2 + 3
y=2t

2007-08-26 13:23:52 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

t = y / 2
x = (y / 2) ² + 3
x = y ² / 4 + 3
4 x = y ² + 12

2007-08-31 01:19:40 · answer #1 · answered by Como 7 · 3 0

I've never heard of a rectangular equation. I think you mean write in rectangular coordinates.

t^2 = (y^2)/4 so x=(y^2)/4 + 3 or 4x-(y^2)-3 = 0

2007-09-03 14:13:31 · answer #2 · answered by rwbblb46 4 · 0 1

im nt sure if this is write but from what i did on my note pad it seems right im only 11 so dont be surprrised if its wrong

t = y / 2
x = (y / 2) ² + 3
x = y ² / 4 + 3
4 x = y ² + 12

If its write can you lz ote me as best answer

2007-09-03 12:26:16 · answer #3 · answered by Anonymous · 0 0

t=y/2
x=y^2/4+3
y^2=4x-12

2007-09-03 09:03:49 · answer #4 · answered by Mugen is Strong 7 · 0 0

t = y / 2..........substitute into the other...........x = ( y / 2)^2 +3 , or x = ( y^2) /4 +3

2007-08-26 20:32:32 · answer #5 · answered by Mathguy 5 · 0 0

t = +- Sqrt( x - 3 )

y = +-2 * Sqrt( x - 3 )

+- means "plus or minus" I just don't know how to get the nice looking symbol in my answer yet.

2007-08-31 15:49:59 · answer #6 · answered by Merlyn 7 · 0 1

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