30-60-90 triangle help?

Question

If the hypotenuse of a 30-60-90 triangle is 4√3, how do i got about to figure out the length of the 2 legs? Help please

Answer 1

sin 60° = √3 / 2
sin 60° = y / 4√3
y / 4√3 = √3 / 2
y = 12 / 2
y = 6

cos 60° = 1/2
cos 60° = x / 4√3
x / 4√3 = 1/2
x = (4√3) / 2
x = 2√3

Legs are 2√3 and 6

Answer 2

4sqrt3 *sqrt3/2

= 2*3 = 6

4sqrt3 *1/2
=2sqrt 3

or 4 sqrt 3 * sin 30 and 4 sqrt 3 * sin 60

or 4 sqrt 3 * cos 30 and 4 sqrt 3 * cos 60

or 4 sqrt 3 * sin 30 and 4 sqrt 3 * cos 30

Answer 3

The short leg is 2 roots of 3 and the long leg is 6

The short leg is half of the hypotenuse
The long leg is root3 times the short one.