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Consider the reaction of 73.0 g of oxygen as follows:

4Fe + 3O2 2Fe2O3

How many moles of oxygen react?
How many moles of iron must react?
How many moles of product form?
What mass of product forms?

2007-08-26 09:16:08 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Three

Four

Two

Let the product be called P. Molecular weights: O2=32 Fe2O3=P=160

73.0gO2 x 1molO2/32gO2 x 2molP/3molO2 x 160gP/1molP = 243g Fe2O3

2007-08-26 10:44:32 · answer #1 · answered by steve_geo1 7 · 0 0

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