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solve by extracting the square roots. list both the exact solution and hte decimal solution.


thank you

2007-08-26 09:07:44 · 6 answers · asked by Li 1 in Science & Mathematics Mathematics

6 answers

(x - 5) = ± √20
(x - 5) = ± 2√5
x = 5 ± 2√5
x = 9.472 , x = 0.528

2007-08-26 09:48:19 · answer #1 · answered by Como 7 · 2 0

(x-5)^2 = 20
=> x-5 = +/- √20
=> x = 5 +/- √20
=> x = 5 +/- √(4*5)
=> x = 5 +/- 2√5
=> x = 5 + 2√5 OR => x = 5 - 2√5 .......exact solution
AND

=> x = 9.472 OR x = 0.528 ....decimal solution.

2007-08-26 09:19:07 · answer #2 · answered by harry m 6 · 0 1

square root both side ;
x-5 = sqr (20)
x-5 = 4.4721
add 5 to both sides
x-5+5 = 4.4721 +5
x = 9.4721 ( decimal solution)

x = 9.47 (exact solution)

2007-08-26 09:27:50 · answer #3 · answered by wuyex 1 · 0 1

(x - 5)² = 20
x - 5 = √20
x - 5 = 2√5
x = 2√5 + 5
x ≈ 9.4721359549995793928183473374626

2007-08-26 09:19:09 · answer #4 · answered by The Glorious S.O.B. 7 · 1 1

(x-5)^2=20
or x^2-10x+25=20
or x^2-10x+5=0
or x={-(-10)+-sq rt(10^2-4.1.5)}/2.1
or x={10+-sq rt(100-20)}/2
or x={10+-sq rt(80)}/2
or x=5+-sq rt(4^2.5)/2
or x=5+-4sq rt(5)/2
or x=5+-2sq rt(5) ans

2007-08-26 09:23:27 · answer #5 · answered by MAHAANIM07 4 · 1 1

(x-5)^2=20
2x-5*2=20
2x-10=20
2x=20+10
2x=30
x=30:2
x=15

2007-08-26 09:52:20 · answer #6 · answered by little.dot 1 · 0 2

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