A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.8 m/s. The car is a distance d away. The bear is 25 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely.
2007-08-26 08:29:39 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
d=43.17m
Difference between tourist speed and bear speed is 2.2m/s
25m divided by 2.2m/s= 11.36s
11.36s times 3.8m/s= 43.17m
Roughly.....I wouldn't test that in real life. :-D
2007-08-26 08:39:18 · answer #1 · answered by Chris H 2 · 0⤊ 0⤋
*edit* Never mind, it's correct now.
The DIFFERENCE between their speeds (or "closing speed")is:
6.0-3.8 m/s = 2.2 m/s
25 m / 2.2 m/s = 11.36 s ("closing time")
3.8 m/s * 11.36 s = 43.17 m
The tourist runs 43.17 m, and the bear runs 6.0 * 11.36, or 68.16 m
2007-08-26 16:01:27 · answer #2 · answered by skeptik 7 · 0⤊ 0⤋