f(x)= -I x+2 I -3
2007-08-26 07:35:36 · 4 answers · asked by A 2 in Science & Mathematics ➔ Mathematics
The above answer is nonsense: this isn't a parabola.
The vertex of a function like that, with an absolute value, is always wherever the part inside the absolute value switches from positive to negative (meaning, you get the pointy part there). The change in the absolute value effective switches the sign of the slope, so that the graph changes directions there.
So solve: x + 2 = 0
x = -2
f(-2) = - | -2 + 2| - 3 = -0 - 3 = -3
Vertex: (-2, -3)
graph:
http://math.colgate.edu/~kellen/interspace/absvertex.gif
2007-08-26 07:43:02 · answer #1 · answered by сhееsеr1 7 · 0⤊ 0⤋
f(x)=-x-2-3=-x-5 if x>-2
f(x)= x+2-3=x-1 if x<-2
draw the lines and see the intersection point
vertex or turning point will be in parabola graph.
2007-08-26 14:41:54 · answer #2 · answered by iyiogrenci 6 · 0⤊ 1⤋
x=-2 where the lines y= -x-5 for x>-2
and y = x-1 encounter
2007-08-26 14:44:45 · answer #3 · answered by santmann2002 7 · 0⤊ 1⤋
-2,-3 i think
2007-08-26 14:41:11 · answer #4 · answered by Drew T 2 · 0⤊ 1⤋