A wooden cylinder 30.0cm high floats vertically in a tub of water (density = 1.00g/cm^3). The top of the cylinder is 14.1 cm above the surface of the liquid. What is the density of the wood???
2007-08-26 07:35:10 · 3 answers · asked by Susieq1118 2 in Science & Mathematics ➔ Physics
15.9 cm is in the water supporting the whole weight of it.
(15.9/30) *1.00=?
or more simply 15.9/30=
..
2007-08-26 07:47:31 · answer #1 · answered by muddypuppyuk 5 · 0⤊ 0⤋
The portion that is below the surface has pushed water out of the way, or "displaced" it. The weight of the entire object is exactly balanced by the weight of the displaced water - which is why it is floating.
An object's density is defined as its mass divided by its volume. But in this case, we don't need to know either its total mass or its total volume, just how the two numbers compare to those of water. This is acceptable, since in any calculation we would perform, the units would cancel out.
So here we go.
30.0 cm - 14.1 cm = 15.9 cm (the amount of wood under water)
30.0 cm of wood weighs the same as 15.9 cm of water. The wood's density is 15.9/30.0 g/cm^3, or 0.53 g/cm^3
2007-08-26 15:28:34 · answer #2 · answered by skeptik 7 · 0⤊ 0⤋
I'm going to say that the answer would be 0.53g/cm^3.
2007-08-26 14:48:02 · answer #3 · answered by Chris H 2 · 0⤊ 1⤋