the first 1/8 is a fraction then the last part is x+3 over 3.
2007-08-26 07:33:07 · 4 answers · asked by bealsey1 2 in Science & Mathematics ➔ Mathematics
get rid of both the divisors by multiplying both sides with 8 and 3
3(2x + 5) = 8(x + 3)
6x + 15 = 8x + 24
6x - 8x = 24 - 15
-2x = 9
so,
x = -4.5
2007-08-26 07:38:27 · answer #1 · answered by dill 2 · 0⤊ 0⤋
Alright, let's work this out:
(2x + 5) / 8 = (x+3) / 3 --problem
(2x + 5) = 8(x+3)/3 -- multiply 8 across
3(2x + 5) = 8(x + 3) -- multiply 3 across
Now distribute the 3 and 8
(3*2x +3*5) = (8*x + 8*3) -- distribute
6x + 15 = 8x + 24 -- simplified multiplication
15 - 24 = 8x - 6x -- got like terms on same sides
-9 = 2x -- simplified subtraction
-9/2 = x -- solved for x
or
-4.5 = x -- decimal answer
Hope this helps. :)
2007-08-26 14:42:19 · answer #2 · answered by Elian 2 · 0⤊ 0⤋
(2x+5)/8 =(x+3)/3
3(2x+5)=8(x+3)
6x+15=8x+24
15-24 =2x
-9=2x
x=-9/2
2007-08-26 14:38:35 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
1/8*(2x+5)=(x+3)/3
or 3(2x+5)=8(x+3)
or 6x+15=8x+24
or 6x-8x=24-15
or -2x=9
or x=-9/2 ans
2007-08-26 14:41:22 · answer #4 · answered by MAHAANIM07 4 · 0⤊ 0⤋