Also i need 2x^2+2x-12=0
8x^2+10x+3=0
4x^2-25=0
need those done also :)
2007-08-26 07:18:50 · 6 answers · asked by Fantara 1 in Science & Mathematics ➔ Mathematics
6x^2+11x-10 = (3x-2)(2x+5) = 0 => x = 2/3, -5/2
8x^2+10x+3 = (4x+3)(2x+1) = 0 => x = -3/4, -1/2
4x^2-25 = (2x+5)(2x-5) = 0 => x = -5/2, 5/2
2007-08-26 07:23:41 · answer #1 · answered by sahsjing 7 · 1⤊ 1⤋
1. 6x^2+15x - 4x- 10=0
2.2x^2+ 6x-4x-12=0
3. 4x^2-25=0
(2x)^2- (5)^2=0
applying formula
(2x-5)(2x+5)=0
so here r d factors
2007-08-26 14:25:47 · answer #2 · answered by harsh_mkg 3 · 0⤊ 1⤋
2x^2+2x-12=0
2(x^2+x-6)=0
2(X-2)(X+3)=0
4x^2-25=0
(2X-5)(2X+5)=0
TRY THE OTHERS
2007-08-26 14:28:19 · answer #3 · answered by iyiogrenci 6 · 0⤊ 1⤋
6x^2+11x-10=0
you have to find 2 nos whose sum=11(b) & whose product is -60(a.c)
or 6x^2-4x+15x-10=0
or 2x(3x-2)+5(3x-2)=0
or (3x-2)(2x+5)=0,Try to solve others,it will improve your skills.
2007-08-26 14:37:15 · answer #4 · answered by MAHAANIM07 4 · 0⤊ 1⤋
Answers:
1) -5 and -4/3
2)-6 and 4
3)-3/2 and -1
4)5/2
2007-08-26 14:30:31 · answer #5 · answered by EinsteinHawking 1 · 0⤊ 2⤋
(3x - 2)(2x + 5)
=]
2007-08-26 14:28:09 · answer #6 · answered by Anonymous · 0⤊ 1⤋