[(x+1)/x] - [x/(x+1)] = 0
2007-08-26 06:58:46 · 9 answers · asked by melle 2 in Science & Mathematics ➔ Mathematics
Multiply each term by x(x+1),
(x+1)^-x^2 = 0, x ≠ 0, -1
2x+1 = 0
x = -1/2
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Ideas to save time: a^2-b^2 = (a+b)(a-b) => (x+1)^-x^2 = 2x+1
2007-08-26 07:02:43 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
Multiply each term by x(x+1),
(x+1)^-x^2 = 0, x â 0, -1
2x+1 = 0
x = -1/2
2007-08-26 14:05:09 · answer #2 · answered by Joe B 2 · 0⤊ 0⤋
[(x+1)/x] - [x/(x+1)] = 0
[(x+1)^2/x(x+1)] - [x^2/x(x+1)] = 0
(x+1)^2 - x^2 = 0
and also verify of x = 0 and or x = -1 are solutions.
they are not.
solving the rest
(x+1)^2 - x^2 = 0
2x + 1 = 0 => x = -0.5
2007-08-26 14:04:52 · answer #3 · answered by gjmb1960 7 · 0⤊ 0⤋
[(x + 1)^2 - x^2]/(x)(x + 1) = 0
(x^2 + 2x + 1 - x^2)/(x)(x + 1) = 0
2x + 1 = 0
x = -1/2
2007-08-26 14:03:40 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2 points
2007-08-26 14:07:17 · answer #5 · answered by Anonymous · 0⤊ 1⤋
I would try this:
[(x+1)/x] - [x/(x+1)] = 0
[(x+1)/x] = [x/(x+1)]
(x+1) / x = x / (x+1)
As long as x does not = 0, and does not = -1, we can get:
(x+1)^2 = x^2
x = -1/2
Check answer:
[(0.5)/(-0.5)] ?= [-0.5/(0.5)]
-1 ?= -1
True, so the answer checks.
2007-08-26 14:08:46 · answer #6 · answered by morningfoxnorth 6 · 0⤊ 0⤋
(x+1)^2-x^2/x(x+1)=0
x^2+2x+1-x^2=0
2x+1=0
x=-1/2.
2007-08-26 14:08:18 · answer #7 · answered by suba 1 · 0⤊ 0⤋
(X+1)/X=X/(X+1)
X2=X2+2X+1
2X=-1
X= -1/2
2007-08-26 14:12:54 · answer #8 · answered by walaa 1 · 0⤊ 0⤋
[(x+1)/x]-[x/(x+1)]=0
(1x/1x)-(1x/1x)
x-x=0
x=1/2
[(1/2+1)/1/2]-[1/2/(1/2+1)]=0
[(11/2)/(1/2)]-[(11/2)/(1/2)=0
(1/2)/(1/2)=0
2007-08-26 14:12:36 · answer #9 · answered by charlie_pace<3 2 · 0⤊ 0⤋