Let sin u = 2/3 and cos v = 2/3 where 0 < u and v < π/2. Find sin (v + u)?

1 ⤊

Let sin u = 2/3 and cos v = 2/3 where 0 < u and v < π/2. Find sin (v + u)?

Please show your work. Thanks. =]

2007-08-26 05:50:36 · 3 answers · asked by mcmigs4 1 in Science & Mathematics ➔ Mathematics

3 answers

sin (v + u)
= sin u cos v + cos u sin v
= (2/3) (2/3) + (2/3) (2/3)
= 8/9

2007-08-26 07:24:22 · answer #1 · answered by Como 7 · 1⤊ 0⤋

sin u = 2/3
since you need sine of v:
cos= - Sin therefore sin v = - 2/3 ( now just substitute)
so Sin (-2/3 + 2/3) = SIN (0) = 0

I could be wrong =)

2007-08-26 13:06:03 · answer #2 · answered by chrys989 2 · 0⤊ 0⤋

If u and v <Ï/2 and sinu=cos v --> u and v are complem.
--> u+v=Ï/2 -->sin(u+v)=sin(Ï/2)=1
Saludos.

2007-08-26 13:24:17 · answer #3 · answered by lou h 7 · 0⤊ 0⤋