Problem from complex numbers....plz help soon.....?

Question

find the modulus of 1+i(3pi)/5

Answer 1

The modulus of a complex number is the square root of the sum of the squares of the real and imaginary components; in essence, the distance from the origin.

Thus, we compute: sqrt(1^2 + ((3pi)/5)^2)
= sqrt(1+ (9pi^2)/25)

Answer 2

Desired modulous=sqrt[1^2+(3pi/5)]^2]
=sqrt[1+9pi^2/25].

Answer 3

let v = (1/5) [1 + i (3π) ]
| v | = (1/5) [ 1² + (3π) ² ]^(1/2)
| v | = (1/5) [ 1 + 88.8]^(1/2)
| v | = (1/5) (99.8)^(1/2)
| v | = 2.0 ( to 1 decimal place)