2007-08-26 04:19:06 · 5 answers · asked by enchel 1 in Science & Mathematics ➔ Chemistry
H2CO3 + H2O <=>H3O+ + HCO3(-)
HCO3(-) + H2O <=> H3O+ + CO3(2-). CO3(2-) will be formed only in the presence of a strong base, the ionization constant is very small
2007-08-26 04:23:31 · answer #1 · answered by Chris 5 · 0⤊ 5⤋
H2CO3 + H2O = HCO3 + H3O
HCO3 + H2O = CO3 + H3O
2007-08-26 11:32:25 · answer #2 · answered by TP_JR 2 · 0⤊ 0⤋
H2CO3 + H2O -> H3O+ + HCO3-
HCO3- + H2O -> H3O+ + CO3(2-)
2007-08-26 11:28:04 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋
H2CO3 + H2O <----> HCO3- + H3O+
HCO3- + H2O <-----> CO32- + H3O+
2007-08-26 11:23:07 · answer #4 · answered by Dr.A 7 · 0⤊ 0⤋
This might depend upon if you usually use free protons or hydronium ions.
H2CO3 (aq) --> HCO3- (aq) + H+ (aq)
HCO3- (aq) --> CO32- (aq) + H+ (aq)
or
H2CO3 (aq) + H2O (l) --> HCO3- (aq) + H3O+ (aq)
HCO3- (aq) + H2O (l) --> CO32- (aq) + H3O+ (aq)
2007-08-26 11:28:04 · answer #5 · answered by Richard 7 · 10⤊ 0⤋