help with equations please?

Question

If I solve for y in the equation 7y+6x = 10, is it that y = 10/7?

If I solve for y in the equation (1/4)y-7x = (15/2), is it that y = 30?

If these are the wrong answers, you any answer kindly show me how to get the right answers?

Thank you.

Answer 1

Question 1
7y = 10 - 6x
y = (1/7) (10 - 6x)
y = 10/7 when x = 0

Question 2
y - 28x = 30
y = 28x + 30
y = 30 when x = 0

Answer 2

Is this part of a question you need to solve?

Basically, for solving questions with 2 unknowns, you need to come up with 2 equations before you can solve.

So you cannot really solve both equations because you need 2 equations first before you can solve the equation. Either by the substitution method or simultaneous method.

So my conclusion is I think your answer is wrong. You need to come up with another equation first. And I cannot help you because I cannot generate another equation from the same equation. It must be a new equation. I need to see what question it is. I'm sorry.

Answer 3

in the first eq when you solve for y you get y=(10-6x)/7

in the second you get y=((15/2)+7x)*4=30-28x

the x does not disappear when you are solving for y

Answer 4

y= (10-6x)/7
y= 30+28x
Your values are only right for x=0

Answer 5

These are equations of lines, asumming an infinite number of (x,y) points along them, a real y for every real x. You can recast them in slope-intercept form to show a solution ofr y as a linear function of x if that is what is desired.