6X^2+7X-3=0
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i really need help
2007-08-25 22:52:41 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(3X - 1) (2X + 3) = 0
X = 1 / 3 , X = - 3 / 2
Method
First find factors of 6x²
Try 3x and 2x
(3x****) (2x****)
Now find factors of 3 that combine with 3x and 2x to give 7x
Try 1 and 3
(3x****1)(2x****3)
Now assign + and - signs to give + 7x and - 3
(3x - 1)(2x + 3) = 0
Either (3x - 1) = 0 or (2x + 3) = 0
x = 1/3 , x = - 3/2
This type of problem becomes straightforward with practice.
2007-08-26 00:01:00 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Factorize the left side of the equation: 6X² + 7X - 3 = 0 by writing it as:
6X² + 9X - 2X - 3 = 0
or 3X(2X + 3) - (2X + 3) = 0
or (2X + 3)(3X - 1) = 0.
Now since the product of two factors is zero any one of them can be zero.
Therefore, either (2X + 3) = 0 or (3X - 1) = 0.
If (2X + 3) = 0 ---> X = - 3/2 and if (3X - 1) = 0 ---> X = 1/3.
Hence the solutions are: either X = - 3/2 or X = 1/3.
2007-08-25 23:03:25 · answer #2 · answered by quidwai 4 · 1⤊ 1⤋
6x^2 + 7x - 3 = 0
(2x + 3)(3x - 1) = 0
2x + 3 = 0 or 3x - 1 = 0
x = -3/2 or x = 1/3
2007-08-25 23:12:39 · answer #3 · answered by Anonymous · 1⤊ 1⤋
6X^2+7X-3=0
(3x-1)(2x+3)=0
3x-1=0 or 2x+3=0
x=1/3 x=-3/2
2007-08-25 23:29:02 · answer #4 · answered by Anonymous · 1⤊ 0⤋
6x^2+7x-3 = 0
x = -7(+-)â[(7)^2-4*6*(-3)] / (2*6)
x = -7(+-)â121 / 12
x = -7(+-) 11 / 12
x = -7-11/12 or -7+11/12
x = -18/12 or 4/12
x = -3/2 or 1/3
2007-08-25 23:50:08 · answer #5 · answered by gab BB 6 · 0⤊ 1⤋
6X^2+7X-3
= (2X+3)*(3X-1)=0
the equqtion equals zero
so
2X+3=0
X=-3/2
or
3x-1=0
x=1/3
regards ;)
2007-08-26 02:34:18 · answer #6 · answered by arwa s. 2 · 0⤊ 1⤋
all the answers above r rite :):P
2007-08-25 23:48:37 · answer #7 · answered by Tw!NkLe 3 · 0⤊ 2⤋