2007-08-25 17:26:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
can you please explain your steps?
2007-08-25 17:34:43 · update #1
x = [ - 6 ± √(36+12) ] / 2
x = [- 6 ± √48 ] / 2
x = [- 6 ± 4√3 ] / 2
x = [- 3 ± 2√3 ] / 2
2007-08-26 00:06:17 · answer #1 · answered by Como 7 · 1⤊ 1⤋
x² + 6x - 3 = 0
You can using quadratic formula or completing the square. You can't do the trinomial method or cross multiplication method because the solution cannot be determined.
Quadratic formula
a = 1 , b = 6 , c = -3
x = -b ± (âb² - 4ac) / 2a >>>Just plug the number into variable
x = -6 ± (â6² - 4(1)(-3)) / 2(1)
x = -6 ± â36 + 12 / 2
x = -6 ± â48 / 2
x = -6 + â48 / 2
x = 0.464 >>>3 decimal point
x = -6 - â48 / 2
x = -6.464 >>>3 decimal point
Thus x = 0.464 or x = -6.464
2007-08-25 17:35:11 · answer #2 · answered by Anonymous · 1⤊ 0⤋
use the quadratic formula
ax² + bx + c
x = (-b ± â (b² - 4ac)) / 2a
x = (-6 + â(6² + 12) / 2
and
x = (-6 - â(6² + 12) / 2
x = (-6 - 6.93) / 2
and
x = (-6 + 6.93) / 2
x = -6.465 , 0.465
2007-08-25 17:35:41 · answer #3 · answered by Jay 4 · 1⤊ 1⤋
x^2 + 6x - 3 = 0
x = -6.4641 . . . . and .. . and . . . x = 0.4641
2007-08-25 17:31:53 · answer #4 · answered by CPUcate 6 · 0⤊ 2⤋