English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

So I know that the angle between A and B is (AdotB)= |A| |B|Cos(theta). But I don't know how to find the angle between A+B

2007-08-25 17:13:25 · 5 answers · asked by math q 2 in Science & Mathematics Mathematics

5 answers

A + B = <5,2> + <1,9> = <6,11>

The x axis is parrallel to the vector <1,0>

So, use the formula you listed and let the new A = <6,11> and the new B = <1,0> and find the angle.

Also, you could just imagine the result of the original A+B = <6,11> as being the hypotenuse of a triangle that start at the origin, goes 6 to the right and 11 up. The angle formedwith the x-axis would be such that Tan(angle) = 11/6 and is in the first quadrant. So, angle = InvTan(11/6)

2007-08-25 17:21:28 · answer #1 · answered by tbolling2 4 · 0 0

B
_
_
_
_
_
_
_ _ _ _A
_ _ _ _ _
it is a right angle triangle as you can see with the height = 7 and breadth = 4. using tangent = opposite over adjacent tangent(angle) = 7/4
shift tan 7/4 = 60.255 degrees. ->answer
understand?
how to get 7: 9-2
how to get 4: 5-1
difference between them makes the length

2007-08-26 00:24:49 · answer #2 · answered by caroline 5 · 0 0

angle of vector A = 21.8014 deg
angle of vector B = 83.6598 deg
sum = 105.4612 deg
angle between = 61.8584 deg

2007-08-26 00:27:03 · answer #3 · answered by CPUcate 6 · 0 0

A+B = <5+1,2+9> = <6,11>
Let angle = t
cos(t) = 6/sqrt(6^2 + 11^2)
= 6 / sqrt(157) = 0.48
t = 61.4 deg

2007-08-26 00:23:22 · answer #4 · answered by vlee1225 6 · 0 0

A + B = (6 11)
Ó¨ = tan^(-1) (11 / 6)
Ө = 61.4° ( to 1 decimal place)

2007-08-26 16:55:37 · answer #5 · answered by Como 7 · 0 0

fedest.com, questions and answers