what is [(x-2)/x]+[(x+4)/(2x)] simplified, show me how to simplify this?

Answer 1

multiply the first part by 2/2 to get
2(x-2)/(2x)+(x+4)/2x
(2x-4+x+4)/(2x)
3x/2x=3/2

It's okay to multiply by 2/2 since it is the same as multiplying by 1, which doesn't change the equation.

Answer 2

Given

[ ( x - 2 ) / x ] + [ ( x + 4 ) / 2x ]

Multiply the first term [ (x - 2 ) / x ] by 2 / 2 so that it has the same denominator as the second term.

[ ( x - 2 ) / x ] * ( 2 / 2 ) = [ ( 2x - 4 ) / 2x ]

Substitute that into the equation.

[ ( 2x - 4 ) / 2x ] + [ ( x + 4 ) / 2x ]

Now that you have common denominators, add the numerators together by combining like terms.

[ ( 2x - 4 ) / 2x ] + [ ( x + 4 ) / 2x ] = ( 2x - 4 + x +4 ) / 2x

Combine like terms.

( 3x + 0 ) / 2x = 3x / 2x

Cancel out the "x".

3x / 2x = 3 / 2

Answer.

3 / 2

Answer 3

First make the denominators of the fractions equal. Multiply the top and bottom of the first fraction by 2.

[(2x - 4)/2x] + [(x + 4)/2x]

which can be rewritten as

(2x - 4 + x + 4)/2x

= 3x / 2x

= 3/2

Answer 4

[(x - 2) / x] + [(x + 4) / (2x)]
= [2(x - 2) / 2(x)] + [x + 4 / 2x] >>>Same their denominator
= (2x - 4 / 2x) + (x + 4 / 2x)
= (2x - 4+ x + 4) / 2x
= (2x + x - 4 + 4) / 2x >>>Reorder the term
= 3x / 2x
= 3 / 2 >>>Convert into mixed number
= 1 1/2

Answer 5

[(x-2)/x]+[(x+4)/(2x)]
= (x/x -2/x) + (x/2x + 4/2x)
= 1 - 2/x + 1/2 + 2/x
= 3/2

Answer 6

[ ( x - 2 ) / x ] + [ ( x + 4 ) / ( 2x ) ]
= [ 2(x - 2) + ( x + 4 ) ] / ( 2x ) { take L.C.M
= [ 2x - 4 + x + 4 ] / 2x { remove bracket
= [ 3x ]/ 2x { simplify
= 3/2 ......

Answer 7

(x - 2) / x + (x + 4) / 2x
[ (2)(x - 2) + (x + 4) ] / 2x
[ 2x - 4 + x + 4 ] / 2x
3x / 2x
3 / 2

Answer 8

[(x-2)/x] + [(x+4)/(2x)]
x/x=1 ___ x/2x=1/2
-2/x=-2 __ 4/2x=2x
[1-2] + [1/2+2x]
-1+1/2+2x
-1/2+2x