2007-08-25 13:29:02 · 6 answers · asked by jumba 1 in Science & Mathematics ➔ Mathematics
(3x^2+6x^3)/9x
=3x(x+2x^2)/9x
=(x+2x^2)/3
2007-08-25 13:37:45 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
[Assuming the first two terms are both in the numerator]
1. Do each of the two terms separately:
3x^2/9x = (1/3)x.
6x^3/9x = (2/3)x^2.
2. Add them, and factor out (1/3)x:
(1/3)x*[1+2x].
2007-08-25 20:34:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
First lets clean up the division.
The x denomintor cancels with one x of the x^3 to give x^2
So now we have
3x^2 + 6x^2/9
Now both are x^2 so we can separate that common factor.
x^2(3+6/9) = 3 2/3 x^2
2007-08-25 20:45:45 · answer #3 · answered by Googleplex 2 · 0⤊ 0⤋
(3x^2) + (6x^3) / (9x)
= 3x^2 + (2/3)x^2
= (3 + 2/3)x^2
= (11/2)x^2
2007-08-25 21:10:28 · answer #4 · answered by sv 7 · 0⤊ 0⤋
(3x^2) + [(6x^3) / (9x)]
= 3x^2 + (2/3)x^2
= (11/3)x^2
2007-08-25 20:33:39 · answer #5 · answered by sahsjing 7 · 1⤊ 0⤋
Assuming question is:-
[ 3 x² (1 + 2x) ] / 9 x
(x / 3) (1 + 2x)
2007-08-26 07:36:47 · answer #6 · answered by Como 7 · 1⤊ 0⤋