log(^x)32=5
can u answer that?
2007-08-25 12:35:38 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
log base x of 32 = 5
x^5 = 32
x = 2
2007-08-29 11:04:58 · answer #1 · answered by Como 7 · 0⤊ 0⤋
I think you are saying log base x of 32 = 5. This is the same thing as saying,
x^5 = 32
Note that 32 = 2^5 so, x must be 2.
2007-08-25 19:39:13 · answer #2 · answered by tbolling2 4 · 0⤊ 0⤋
If you mean log to base x of 23 = 5, then x=2 because 2^5=32.
You should learn proper notation. wWhy not copy the problem precisely as it is written?
2007-08-25 19:43:49 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
log(base x)32 = 5
x^5 = 32
x = 2
2007-08-25 19:38:19 · answer #4 · answered by holdm 7 · 0⤊ 0⤋
Usually when you first do logs the best way to see the answer is to rewrite it in exponential notation. You must have just gotten the notes on how to do that. After that , it's usually a matter of simple algebra to solve for x.
2007-08-25 19:40:47 · answer #5 · answered by douglas 2 · 0⤊ 0⤋